On Tue, 9 Dec 2003, Henry Sobotka wrote:
2009. I would expect 9-12-2003 (expressing years in two digits is
frowned upon; e.g. 1998-99 is considered an anglicism, the proper way
to write it being 1998-1999). The string version would be le 9
décembre 2003; month abbreviations tend to be used
Hi All,
I am kinda stuck creating a DateTime parser.
The dates I am trying to parse are:
06/26/98
06-26-98
Jun 26 1998
Jun 26 98
I have the first two done and working but the third and forth is giving
me fits :(
Here is what I have tried;
I created a new package like so,
package
Hi Rick,
On Tue, 9 Dec 2003 12:29:33 -0800 , Hill, Ronald wrote
my $dt = DateTime::Format::UGAnswer-parse_date('Jan 26 2001');
print $dt-mdy;
I have tried messing with this line in the package
strptime = '%B%N%d%N%Y' in order to get it to work but nogo
%N is
On Tue, 9 Dec 2003 12:29:33 -0800 , Hill, Ronald wrote
my $dt = DateTime::Format::UGAnswer-parse_date('Jan 26 2001');
print $dt-mdy;
I have tried messing with this line in the package
strptime = '%B%N%d%N%Y' in order to get it to work but nogo
%N is nanoseconds. You might want to