Bug#881098: unbuffered pee

[Dima Kogan]

I looked at the sources just now, and it does this:

        for (i = 1; i < argc; i++) {
                pipes[i - 1] = popen(argv[i], "w");
                ...
                setbuf(pipes[i - 1], NULL);
        }

I.e. each pipe is already unbuffered. Matthew, can you confirm that you
are indeed seeing buffered output?