Package: gcc-4.3
Version: 4.3.3-13
Severity: normal
When using -fvisibility=hidden to define the global visibility to hidden,
declaring a function with the global visibility, then redeclaring it
with visibility default results in the symbol being exported.
$ cat test.c EOF
extern int foo();
On Sat, Jul 11, 2009 at 10:58:46AM +0200, Mike Hommey wrote:
When using -fvisibility=hidden to define the global visibility to hidden,
declaring a function with the global visibility, then redeclaring it
with visibility default results in the symbol being exported.
Pleas rered the
On Sat, Jul 11, 2009 at 12:00:58PM +0200, Bastian Blank wrote:
On Sat, Jul 11, 2009 at 10:58:46AM +0200, Mike Hommey wrote:
When using -fvisibility=hidden to define the global visibility to hidden,
declaring a function with the global visibility, then redeclaring it
with visibility default
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