[10-31]) SearchStr=$Month $Day;;
That means a single character in the set 1, 0 through 3, and 1, so
it will match any of 0 1 2 3 and nothing else.
# [12][0-9]) SearchStr=$Month $Day;;
# 30 | 31 ) Day=02; SearchStr=$Month 9;;
That's more like it; the [12][0-9] will match 10
Oliver Elphick writes:
On the other hand, this does not properly handle invalid day/month
combinations, such as 31 February. Do you handle that somewhere else?
Use the 'date' command. For example:
date +%D --date '1/1/97 +60days'
returns:
03/02/97
Like most GNU utilities,
Hello all - I have a KSH script question...
sorry - the offending line is [10-31]) not [30-31])
Can someone out there take a look at this script. I want to perform an
operation based on the day of month. but the days (10 - 31) are giving
me a problem. I would really like to keep this a one liner
David Oswald wrote:
Hello all - I have a KSH script question...
sorry - the offending line is [10-31]) not [30-31])
What `[10-31]' says is: match any single character which is a 1, a character
from 0 to 3 inclusive, or (another) 1. What you want is `[12][0-9]|3[0-1]'.
On the other hand,
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