Jonathan Matthews wrote:
On Sat, Jun 28, 2003 at 03:03:27PM +0100, David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
[snip]
for N in 1 2 3 4 5 6 7 8 9
do
echo $N
done
I'm
On Sat, June 28 at 3:03 PM EDT
David selby [EMAIL PROTECTED] wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My
On Sat, 2003-06-28 at 10:03, David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess is
El(On) 28/06/2003 (15:03:27), David selby escribió(wrote):
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess
On Sat, Jun 28, 2003 at 03:03:27PM +0100, David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
[EMAIL PROTECTED]:~$ cat ./bashtest
#!/bin/bash
i=0
while
To: Debian list
Subject: simple bash loop problem ...
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess
* David selby [EMAIL PROTECTED] [030629 18:42]:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess is
How about
for N in `seq 1 9`
do...?
--Todd
On Sun, 29 Jun 2003 09:55:00 +
Jonathan Matthews [EMAIL PROTECTED] wrote:
On Sat, Jun 28, 2003 at 03:03:27PM +0100, David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to
On Mon, 30 Jun 2003 05:30:14 +0200, Sebastian Kapfer wrote:
n=1
while [ $n \ 9 ]; do
echo $n
n=$((n+=1))
done
Note the backslash. Plain is for redirection. Interesting to see that I
never ran into this thing, because I'm used to != from C++ :-)
Of course \ is still wrong,
David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess is
declare -i n=1
while [ $n 9 ]; do
.
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess is
declare -i n=1
while [ $n 9 ]; do
.
n=$((n+=1))
done
All i get
On Sat, Jun 28, 2003 at 03:03:27PM +0100, David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
[snip]
for N in 1 2 3 4 5 6 7 8 9
do
echo $N
done
I'm sure someone will point out a
David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess is
declare -i n=1
while [ $n 9 ]; do
.
On Sat, Jun 28, 2003 at 03:03:27PM +0100, David selby wrote:
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
[...]
My best guess is
declare -i n=1
while [ $n 9 ]; do
.
n=$((n+=1))
done
All
On Sun, 29 Jun 2003 11:50:06 +0200, David selby wrote:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
[...]
kind of thing, but this is not BASIC !!
... and honestly, I'm glad it isn't BASIC
David selby schrieb:
PS is there a more ellagent way to do a counted loop as well as a way
that works ?
This should do it:
for ((n=1; n 9; n++))
do
...
done
Maddin
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Am Sam, 2003-06-28 um 16.03 schrieb David selby:
Hello,
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
kind of thing, but this is not BASIC !!
My best guess is
On Sat, Jun 28, 2003 at 03:03:27PM +0100, David selby wrote:
I am writing bash a bash sed script, it has been going suprisingly
well. I need a loop to count 9 times the variable n to the count ..
for n=1 to 9
next
for n in $(seq 1 9); do
...
done
kind of thing, but this
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