On tir, 2005-12-06 at 22:33, Bernt M. Johnsen wrote:
Craig L Russell wrote (2005-12-06 10:31:57):
Hi Joe,
I think your problem is that VARCHAR needs a length, so the ) in
the user_password VARCHAR) (at position 161) was unexpected. It
expected (20) before the closing ).
For the
Lars Clausen wrote (2005-12-07 09:46:40):
On tir, 2005-12-06 at 22:33, Bernt M. Johnsen wrote:
Craig L Russell wrote (2005-12-06 10:31:57):
Hi Joe,
I think your problem is that VARCHAR needs a length, so the ) in
the user_password VARCHAR) (at position 161) was unexpected. It
Perhaps you made a typo when you posted this but from what I see you did not
specify the length of the user_password field you simply indicated the
datatype VARCHAR.
-Samer
-Original Message-
From: Joe Siebenmann [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 06, 2005 12:07 PM
To:
Hi Joe,I think your problem is that VARCHAR needs a length, so the ")" in the "user_password VARCHAR)" (at position 161) was unexpected. It expected (20) before the closing ")".Best,CraigOn Dec 6, 2005, at 10:06 AM, Joe Siebenmann wrote:Hi All,I'm trying to create my initial database tables using
Craig L Russell wrote (2005-12-06 10:31:57):
Hi Joe,
I think your problem is that VARCHAR needs a length, so the ) in
the user_password VARCHAR) (at position 161) was unexpected. It
expected (20) before the closing ).
For the record: VARCHAR without length is a non-standard feature
