Thanks Mayur - based on the doc-comments in source looks like this will
work for the case. I will confirm.
the dreamers of the day are dangerous men, for they may act their dream
with open eyes, and make it possible
On Fri, Mar 7, 2014 at 2:21 AM, Mayur Rustagi
Hi All,
I have a three machine cluster. I have two RDDs each consisting of (K,V)
pairs. RDDs have just three keys 'a', 'b' and 'c'.
// list1 - List(('a',1), ('b',2),
val rdd1 = sc.parallelize(list1).groupByKey(new HashPartitioner(3))
// list2 - List(('a',2), ('b',7),
