Re: std.math.TAU

2011-07-05 Thread Walter Bright
On 7/5/2011 11:12 PM, KennyTM~ wrote: On Jul 6, 11 06:59, Walter Bright wrote: It's definitely not good enough to just write some simple fp program to generate them. http://www.wolframalpha.com/input/?i=pi+in+hexadecimal sweet!

Re: std.math.TAU

2011-07-05 Thread KennyTM~
On Jul 6, 11 06:59, Walter Bright wrote: On 7/5/2011 3:45 PM, Don wrote: Another thing -- why are some constants defined in decimal, others in hex, and one (E) with the long 'L' suffix? The ones defined in decimal are obsolete, they haven't had a conversion to hex yet. The ones in hex I got

Re: std.math.TAU

2011-07-05 Thread Walter Bright
On 7/5/2011 3:45 PM, Don wrote: Another thing -- why are some constants defined in decimal, others in hex, and one (E) with the long 'L' suffix? The ones defined in decimal are obsolete, they haven't had a conversion to hex yet. The ones in hex I got out of a book that helpfully printed them

Re: std.math.TAU

2011-07-05 Thread Don
James Fisher wrote: On Tue, Jul 5, 2011 at 8:49 PM, Don > wrote: James Fisher wrote: On Tue, Jul 5, 2011 at 12:31 PM, James Fisher mailto:jameshfis...@gmail.com> __>> wrot

Re: std.math.TAU

2011-07-05 Thread James Fisher
On Tue, Jul 5, 2011 at 8:49 PM, Don wrote: > James Fisher wrote: > > On Tue, Jul 5, 2011 at 12:31 PM, James Fisher > jameshfis...@gmail.com**>> wrote: >> >>Sorry, I didn't state this very clearly. Multiplying the >>approximation of PI in std.math should yield the exact double of >>t

Re: std.math.TAU

2011-07-05 Thread Don
James Fisher wrote: On Tue, Jul 5, 2011 at 12:31 PM, James Fisher > wrote: Sorry, I didn't state this very clearly. Multiplying the approximation of PI in std.math should yield the exact double of that approximation, as it should just involve increasin

Re: std.math.TAU

2011-07-05 Thread James Fisher
On Tue, Jul 5, 2011 at 12:15 PM, Steven Schveighoffer wrote: > > I read an article about this recently, it's definitely interesting. The > one place where I haven't seen it mentioned is what happens when you want > the area of a circle, since that necessarily involves the radius. I'd guess > you'

Re: std.math.TAU

2011-07-05 Thread Nick Sabalausky
"James Fisher" wrote in message news:mailman.1426.1309854678.14074.digitalmar...@puremagic.com... >Hopefully this won't be taken as frivolous. I (and possibly some of you) >have been convinced by the argument at http://tauday.com/. It's very >convincing, and I won't rehash it here. He had me a

Re: std.math.TAU

2011-07-05 Thread James Fisher
On Tue, Jul 5, 2011 at 12:31 PM, James Fisher wrote: > > Sorry, I didn't state this very clearly. Multiplying the approximation of > PI in std.math should yield the exact double of that approximation, as it > should just involve increasing the exponent by 1. However, [double the > approximation o

Re: std.math.TAU

2011-07-05 Thread James Fisher
On Tue, Jul 5, 2011 at 12:15 PM, Steven Schveighoffer wrote: > On Tue, 05 Jul 2011 04:31:09 -0400, James Fisher > wrote: > > Hopefully this won't be taken as frivolous. I (and possibly some of you) >> have been convinced by the argument at http://tauday.com/. It's very >> convincing, and I won

Re: std.math.TAU

2011-07-05 Thread Steven Schveighoffer
On Tue, 05 Jul 2011 04:31:09 -0400, James Fisher wrote: Hopefully this won't be taken as frivolous. I (and possibly some of you) have been convinced by the argument at http://tauday.com/. It's very convincing, and I won't rehash it here. The use of τ instead of π will only become really co