On Sunday, 3 July 2016 at 13:41:27 UTC, Ola Fosheim Grøstad wrote:
On Sunday, 3 July 2016 at 11:49:15 UTC, Andrei Alexandrescu
wrote:
Well to be more precise here's what I'm looking for. When you
compare an integral with a floating point number, the integral
is first converted to floating point
On Sunday, 3 July 2016 at 11:49:15 UTC, Andrei Alexandrescu wrote:
Well to be more precise here's what I'm looking for. When you
compare an integral with a floating point number, the integral
is first converted to floating point format. I.e. for long x
and double y, x == y is the same as double
On 07/03/2016 05:52 AM, Guillaume Boucher wrote:
On Sunday, 3 July 2016 at 09:08:14 UTC, Ola Fosheim Grøstad wrote:
On Saturday, 2 July 2016 at 20:17:59 UTC, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is convertible
to a floating point value precisely (i.e.
On Sunday, 3 July 2016 at 09:52:38 UTC, Guillaume Boucher wrote:
This is the correct answer for another definition of "precisely
convertible", not the one Andrei gave.
True, I see now that he actually asked for unique representation,
not precisely convertible.
On Sunday, 3 July 2016 at 09:08:14 UTC, Ola Fosheim Grøstad wrote:
On Saturday, 2 July 2016 at 20:17:59 UTC, Andrei Alexandrescu
wrote:
So what's the fastest way to figure that an integral is
convertible to a floating point value precisely (i.e. no other
integral converts to the same floating p
On Saturday, 2 July 2016 at 20:17:59 UTC, Andrei Alexandrescu
wrote:
So what's the fastest way to figure that an integral is
convertible to a floating point value precisely (i.e. no other
integral converts to the same floating point value)? Thanks! --
Andrei
If it is within what the mantissa
On Saturday, 2 July 2016 at 20:30:03 UTC, Walter Bright wrote:
On 7/2/2016 1:17 PM, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is
convertible to a
floating point value precisely (i.e. no other integral
converts to the same
floating point value)? Thanks! --
On Saturday, 2 July 2016 at 20:49:27 UTC, Andrei Alexandrescu
wrote:
On 7/2/16 4:30 PM, Walter Bright wrote:
On 7/2/2016 1:17 PM, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is
convertible to a
floating point value precisely (i.e. no other integral
converts
On Saturday, 2 July 2016 at 20:17:59 UTC, Andrei Alexandrescu
wrote:
So what's the fastest way to figure that an integral is
convertible to a floating point value precisely (i.e. no other
integral converts to the same floating point value)? Thanks! --
Andrei
bool isConvertible(T) (long n) if
On 7/2/2016 1:49 PM, Andrei Alexandrescu wrote:
On 7/2/16 4:30 PM, Walter Bright wrote:
On 7/2/2016 1:17 PM, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is convertible to a
floating point value precisely (i.e. no other integral converts to the
same
floating p
On Saturday, 2 July 2016 at 20:49:27 UTC, Andrei Alexandrescu
wrote:
On 7/2/16 4:30 PM, Walter Bright wrote:
On 7/2/2016 1:17 PM, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is
convertible to a
floating point value precisely (i.e. no other integral
converts
On 7/2/16 4:30 PM, Walter Bright wrote:
On 7/2/2016 1:17 PM, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is convertible to a
floating point value precisely (i.e. no other integral converts to the
same
floating point value)? Thanks! -- Andrei
Test that its ab
On 7/2/2016 1:17 PM, Andrei Alexandrescu wrote:
So what's the fastest way to figure that an integral is convertible to a
floating point value precisely (i.e. no other integral converts to the same
floating point value)? Thanks! -- Andrei
Test that its absolute value is <= the largest unsigned v
So what's the fastest way to figure that an integral is convertible to a
floating point value precisely (i.e. no other integral converts to the
same floating point value)? Thanks! -- Andrei
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