On 2012-01-04 20:14, Alex Rønne Petersen wrote:
Hi,
When using __gshared for variables at module level, it is my
understanding that they should be initialized in the shared static this
constructor. My question is: When having __gshared variables inside
classes, where should I initialize these? D
import std.stdio;
void test(T)(lazy T dg)
{
test2(dg);
}
void test2(T)(lazy T dg)
{
dg();// nothing happens
dg()(); // have to use double-invocation instead
}
void main()
{
test({ writeln("test"); });
}
Do you think it would be possible for the compiler to avoid wrapping
de
On 1/5/2012 4:14 AM, Alex Rønne Petersen wrote:
Hi,
When using __gshared for variables at module level, it is my
understanding that they should be initialized in the shared static this
constructor. My question is: When having __gshared variables inside
classes, where should I initialize these? D
On Wednesday, 4 January 2012 at 23:02:24 UTC, Simen Kjærås
wrote:
On Wed, 04 Jan 2012 23:40:28 +0100, Jesse Phillips
wrote:
On Wednesday, 4 January 2012 at 22:19:28 UTC, Caligo wrote:
1. Are there any other solutions ?
2. Would it make sense to have 'out default argument of void'
in D?
Ou
On Wed, Jan 4, 2012 at 4:40 PM, Jesse Phillips
wrote:
>
> Out parameters are initialized. The declaration you want is:
>
> bool fun(double theta, A a = A.init, B b = B.init, C c = C.init){ /* ... */
> }
>
In my case A, B, and C are structs, so that works the way I wanted it. Nice!
It doesn't, ho
On 01/04/2012 02:19 PM, Caligo wrote:
> I have a function that looks something like this:
>
> bool fun(double theta, out A a, out B b, out C c){ /* ... */ }
>
> if fun() returns false, then nothing is supposed to be assigned to a,
> b, c. If it returns true, then values are assigned to a, b, c.
On Wed, 04 Jan 2012 23:19:18 +0100, Caligo wrote:
I have a function that looks something like this:
bool fun(double theta, out A a, out B b, out C c){ /* ... */ }
if fun() returns false, then nothing is supposed to be assigned to a,
b, c. If it returns true, then values are assigned to a, b
On Wed, 04 Jan 2012 23:40:28 +0100, Jesse Phillips
wrote:
On Wednesday, 4 January 2012 at 22:19:28 UTC, Caligo wrote:
1. Are there any other solutions ?
2. Would it make sense to have 'out default argument of void' in D?
Out parameters are initialized. The declaration you want is:
bool fu
On 01/04/2012 11:19 PM, Caligo wrote:
I have a function that looks something like this:
bool fun(double theta, out A a, out B b, out C c){ /* ... */ }
if fun() returns false, then nothing is supposed to be assigned to a,
b, c. If it returns true, then values are assigned to a, b, c. Also,
th
.property = "test";
.method = "test";
.method("test");
What does -property exactly do?
If you had like a dynamic where you don't know if it's
member is a property or a method. You would choose
method right?
scratch the invalid ones below.
---
.property="test";
.pr
> Yeah, D feels like that to me too, sometimes. Anyways, for your question -
> would using the struct name be good enough? They're easy to get hold of
> and usable in switch statements.
>
> If not, how about this:
>
>
> import std.typetuple;
>
> struct TypeEnum( T... ) {
> static pure nothrow @
On Wednesday, 4 January 2012 at 22:19:28 UTC, Caligo wrote:
1. Are there any other solutions ?
2. Would it make sense to have 'out default argument of void'
in D?
Out parameters are initialized. The declaration you want is:
bool fun(double theta, A a = A.init, B b = B.init, C c = C.init){
/*
Hi,
When using __gshared for variables at module level, it is my
understanding that they should be initialized in the shared static this
constructor. My question is: When having __gshared variables inside
classes, where should I initialize these? Do classes have a shared
static this construct
I have a function that looks something like this:
bool fun(double theta, out A a, out B b, out C c){ /* ... */ }
if fun() returns false, then nothing is supposed to be assigned to a,
b, c. If it returns true, then values are assigned to a, b, c. Also,
there are two ways to call fun(): If I'm
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