On Monday, 21 October 2013 at 14:59:54 UTC, Alexandr Druzhinin
wrote:
If you switch instruction order you create local copy and then
set x[0] in local copy so original is unchanged. But local copy
creating depends on several thing and happens not every
appending in general. Your way is not D-is
On Monday, 21 October 2013 at 10:41:38 UTC, Alexandr Druzhinin
wrote:
21.10.2013 17:31, Krzysztof Ciebiera пишет:
void main()
{
int a[][] = [[1,2,3]];
foreach(x; a)
{
x[0] = 0;
x ~= 4;
}
writeln(a);
}
...
&) or [0,2,3,4] (python, C++ ref). But [0,2,3]? It
Is the following compiler behavior consistent with language
specification?
import std.stdio;
void main()
{
int a[][] = [[1,2,3]];
foreach(x; a)
{
x[0] = 0;
x ~= 4;
}
writeln(a);
}
I understand why thw program could output [1,2,3] (like in C++
without &) or
