On Friday, 4 April 2014 at 08:52:09 UTC, Daniel Murphy wrote:
On Friday, 4 April 2014 at 04:10:51 UTC, Saurabh Das wrote:
Hello,
Say I compile a program with:
dmd -unittest -debug -cov test.d
Then, when I run ./test, a file 'test.lst' is generated in the
current working directory. Is there a
On Friday, 4 April 2014 at 04:10:51 UTC, Saurabh Das wrote:
Hello,
Say I compile a program with:
dmd -unittest -debug -cov test.d
Then, when I run ./test, a file 'test.lst' is generated in the
current working directory. Is there a way in which I can
instruct the file to be created in a separ
On 04/03/2014 09:10 PM, Saurabh Das wrote:
> Say I compile a program with:
>
> dmd -unittest -debug -cov test.d
So, that's what the makefile generates. ;) You can have an additional
line that moves the coverage file away.
Ali
After reading some of the bug reports on BugZilla, I gather that
this isn't possible yet :(
Thanks,
Saurabh
On Friday, 4 April 2014 at 04:10:51 UTC, Saurabh Das wrote:
Hello,
Say I compile a program with:
dmd -unittest -debug -cov test.d
Then, when I run ./test, a file 'test.lst' is generat
Hello,
Say I compile a program with:
dmd -unittest -debug -cov test.d
Then, when I run ./test, a file 'test.lst' is generated in the
current working directory. Is there a way in which I can instruct
the file to be created in a separate './cov_log/' directory?
Thanks,
Saurabh