On Tuesday, 12 July 2022 at 14:55:47 UTC, anonymouse wrote:
I've tried using a foreach loop to achieve this but failed
miserably.
--anonymouse
Wait, I think I've got it.
This little snippet does the trick:
int index;
foreach(i, v; a) {
int t = v;
foreach(d;
On Tuesday, 12 July 2022 at 14:17:36 UTC, ananymouse wrote:
Been racking my brain on this for hours. Please point me in the
right direction.
Thanks,
--anonymouse
My current implementation:
``` d
// Allow for indexing to read a value, e.g a[0,0,0]
T opIndex(A...)(A a) {
Given a 3D matrix of shape[3, 5, 7] that is implemented using a
1D array, I can calculate the index of any element (e.g. [1, 0,
6]) as follows:
index = 1 * 5 * 7 + 0 * 7 + 6
In general, if I have a K x L x M matrix, I can access
index[i][j][k] by calculating i*L*M + j*M + k to yield the
