On Sunday, 20 September 2020 at 17:08:49 UTC, realhet wrote:
On Sunday, 20 September 2020 at 16:18:19 UTC, Steven
Schveighoffer wrote:
On 9/20/20 11:52 AM, realhet wrote:
On Sunday, 20 September 2020 at 14:54:09 UTC, Steven
Schveighoffer wrote:
On 9/20/20 9:30 AM, realhet wrote:
Yeah, I think
On Sunday, 20 September 2020 at 16:18:19 UTC, Steven
Schveighoffer wrote:
On 9/20/20 11:52 AM, realhet wrote:
On Sunday, 20 September 2020 at 14:54:09 UTC, Steven
Schveighoffer wrote:
On 9/20/20 9:30 AM, realhet wrote:
Yeah, I think this might work.
-Steve
That would be a 3rd category out i
On 9/20/20 11:52 AM, realhet wrote:
On Sunday, 20 September 2020 at 14:54:09 UTC, Steven Schveighoffer wrote:
On 9/20/20 9:30 AM, realhet wrote:
ref inout(int) x() inout { return array[0]; }
This doesn't work when I type:
v.x++;
It should, as long as v is mutable.
I want to make a similar t
On Sunday, 20 September 2020 at 15:52:49 UTC, realhet wrote:
On Sunday, 20 September 2020 at 14:54:09 UTC, Steven
Schveighoffer wrote:
On 9/20/20 9:30 AM, realhet wrote:
I managed to do the constant swizzles and it seems so elegant:
auto opDispatch(string def)() const
if(validRvalueSwizzl
On Sunday, 20 September 2020 at 14:54:09 UTC, Steven
Schveighoffer wrote:
On 9/20/20 9:30 AM, realhet wrote:
ref inout(int) x() inout { return array[0]; }
This doesn't work when I type:
v.x++;
I want to make a similar type like the GLSL vectors. Where the
following thing is valid:
vec4 a, b;
On 9/20/20 9:30 AM, realhet wrote:
Hi,
struct S{
int[2] array;
ref x() { return array[0]; }
auto x() const { return array[0]; }
}
If there a way to write the function 'x' into one function, not 2
overloads.
I tried auto/const/ref mindlessly :D, also remembered 'inout', but
On Sunday, 20 September 2020 at 13:30:36 UTC, realhet wrote:
Hi,
More specifically:
struct S{
int[2] array;
ref swizzle(string code)(){
static if(code=="x") return array[0];
else static if(code=="y") return array[1];
else static assert("Unhandled");
}
Hi,
struct S{
int[2] array;
ref x() { return array[0]; }
auto x() const { return array[0]; }
}
If there a way to write the function 'x' into one function, not 2
overloads.
I tried auto/const/ref mindlessly :D, also remembered 'inout',
but obviously those weren't solve the probl
