On Sunday, 15 September 2013 at 20:58:54 UTC, Kadir Erdem Demir
wrote:
On Sunday, 15 September 2013 at 15:39:14 UTC, John Colvin wrote:
On Sunday, 15 September 2013 at 15:15:28 UTC, Kadir Erdem
Demir wrote:
I am using fft function from std.numeric
Complex!double[] resultfft =
I think you are not aswering his question (but maybe I am wrong).
If you want a Fourier transform with less frequencies than
temporal samples you can perform a fft to get a result of same
length like this :
9 2 7 6 1 8 (amplitude)
0 2 4 6 8 10 (frequency)
Then transform it like this :
11
I am using fft function from std.numeric
Complex!double[] resultfft = fft(timeDomainAmplitudeVal);
The parameter timeDomainAmplitudeVal is audio amplitude data.
Sample rate 44100 hz and there is 131072(2^16) samples
I am seeing that resultfft has the same size as
On Sunday, 15 September 2013 at 15:15:28 UTC, Kadir Erdem Demir
wrote:
I am using fft function from std.numeric
Complex!double[] resultfft = fft(timeDomainAmplitudeVal);
The parameter timeDomainAmplitudeVal is audio amplitude data.
Sample rate 44100 hz and there is 131072(2^16) samples
I am
On Sunday, 15 September 2013 at 15:15:28 UTC, Kadir Erdem Demir
wrote:
I am using fft function from std.numeric
Complex!double[] resultfft = fft(timeDomainAmplitudeVal);
The parameter timeDomainAmplitudeVal is audio amplitude data.
Sample rate 44100 hz and there is 131072(2^16) samples
I am
On Sunday, 15 September 2013 at 15:39:14 UTC, John Colvin wrote:
On Sunday, 15 September 2013 at 15:15:28 UTC, Kadir Erdem Demir
wrote:
I am using fft function from std.numeric
Complex!double[] resultfft = fft(timeDomainAmplitudeVal);
The parameter timeDomainAmplitudeVal is audio amplitude
On Sunday, 15 September 2013 at 20:58:54 UTC, Kadir Erdem Demir
wrote:
On Sunday, 15 September 2013 at 15:39:14 UTC, John Colvin wrote:
On Sunday, 15 September 2013 at 15:15:28 UTC, Kadir Erdem
Demir wrote:
I am using fft function from std.numeric
Complex!double[] resultfft =
On Sunday, 15 September 2013 at 20:58:54 UTC, Kadir Erdem Demir
wrote:
On Sunday, 15 September 2013 at 15:39:14 UTC, John Colvin wrote:
On Sunday, 15 September 2013 at 15:15:28 UTC, Kadir Erdem
Demir wrote:
I am using fft function from std.numeric
Complex!double[] resultfft =