On 03/04/2011 10:41 AM, Magnus Lie Hetland wrote:
On 2011-03-04 18:08:08 +0100, spir said:
Didn't even know 'in' can be defined with opBinary...
I use opIn_r ('r' for right side, since the container stand on the
right of the expression) everywhere, and it works fine.
Huh. Cool. Works like a c
On 2011-03-04 18:08:08 +0100, spir said:
Didn't even know 'in' can be defined with opBinary...
I use opIn_r ('r' for right side, since the container stand on the
right of the expression) everywhere, and it works fine.
Huh. Cool. Works like a charm. Seems cleaner like the opBinaryRight
soluti
On 03/04/2011 05:01 PM, Magnus Lie Hetland wrote:
I'm writing a collection with functionality for membership checking. I thought
it would be nice to use the "in" operator. In the docs for std.collections I
surmise that this is the standard way to go. From the source code, I see
there's no special
Magnus Lie Hetland wrote:
On 2011-03-04 17:06:29 +0100, Mafi said:
If you try to use it in the manner of `something in
classWhichDefinesThisOpBinary` then it doesn't work because operator
overloading normally overloads on the left operand (ie something). Use
opBinaryRight(string op)(...)
On 2011-03-04 17:06:29 +0100, Mafi said:
If you try to use it in the manner of `something in
classWhichDefinesThisOpBinary` then it doesn't work because operator
overloading normally overloads on the left operand (ie something). Use
opBinaryRight(string op)(...) if(...) to get it working.
Aa
Am 04.03.2011 17:01, schrieb Magnus Lie Hetland:
I'm writing a collection with functionality for membership checking. I
thought it would be nice to use the "in" operator. In the docs for
std.collections I surmise that this is the standard way to go. From the
source code, I see there's no special
I'm writing a collection with functionality for membership checking. I
thought it would be nice to use the "in" operator. In the docs for
std.collections I surmise that this is the standard way to go. From the
source code, I see there's no special opIn, but that it can be done
with the more gen
