On Sunday, 7 December 2014 at 15:47:45 UTC, H. S. Teoh via
Digitalmars-d-learn wrote:
Ok, thanks.
I just noticed that byGrapheme() lacks bidirectional access.
Further
it also lacks graphemeStrideBack() in complement to
graphemeStride()?
Similar to stride() and strideBack(). Is this difficult
On Monday, 8 December 2014 at 14:57:06 UTC, Nordlöw wrote:
What's the best source of information for these algorithms? Is
it certain that graphemes iteration is backwards iteratable by
definition?
I guess
https://en.wikipedia.org/wiki/Combining_character
could be a good start.
On Saturday, 6 December 2014 at 22:37:19 UTC, Nordlöw wrote:
Given the fact that
static assert(é.length == 2);
I was surprised that
static assert(é.byCodeUnit.length == 2);
static assert(é.byCodePoint.length == 2);
string already iterates over code points. So byCodePoint doesn't
On Saturday, 6 December 2014 at 22:37:19 UTC, Nordlöw wrote:
static assert(é.byCodePoint.length == 2);
Huh? Why is byCodePoint.length even defined?
On Sunday, 7 December 2014 at 13:24:28 UTC, Marc Schütz wrote:
On Saturday, 6 December 2014 at 22:37:19 UTC, Nordlöw wrote:
static assert(é.byCodePoint.length == 2);
Huh? Why is byCodePoint.length even defined?
because string has ElementType dchar (i.e. it already iterates by
On Sunday, 7 December 2014 at 13:24:28 UTC, Marc Schütz wrote:
On Saturday, 6 December 2014 at 22:37:19 UTC, Nordlöw wrote:
static assert(é.byCodePoint.length == 2);
Huh? Why is byCodePoint.length even defined?
import std.uni;
pragma(msg, typeof(é.byCodePoint));
= string
Something's
On Saturday, 6 December 2014 at 23:11:49 UTC, H. S. Teoh via
Digitalmars-d-learn wrote:
This is a Unicode issue. What you want is neither byCodeUnit nor
byCodePoint, but byGrapheme. A grapheme is the Unicode
equivalent of
what lay people would call a character. A Unicode character
(or more
On Sun, Dec 07, 2014 at 02:30:13PM +, Nordlöw via Digitalmars-d-learn
wrote:
On Saturday, 6 December 2014 at 23:11:49 UTC, H. S. Teoh via
Digitalmars-d-learn wrote:
This is a Unicode issue. What you want is neither byCodeUnit nor
byCodePoint, but byGrapheme. A grapheme is the Unicode
On Sat, Dec 06, 2014 at 10:37:17PM +, Nordlöw via Digitalmars-d-learn
wrote:
Given the fact that
static assert(é.length == 2);
I was surprised that
static assert(é.byCodeUnit.length == 2);
static assert(é.byCodePoint.length == 2);
Isn't there a way to iterate over
