On Tuesday, 21 April 2015 at 03:44:16 UTC, weaselcat wrote:
snip
Wow, that's a damn good solution... I didn't know that readln()
could take an argument that it stops at once it finds.
Now the thing is, this program is supposed to be a reverse Polish
notation calculator. A human using this p
On Tuesday, 21 April 2015 at 01:31:58 UTC, TheGag96 wrote:
Hi guys! I had this homework assignment for data structures
that has a pretty easy solution in C++. Reading input like
this...
1 2 3 # $
4 3 * ! #
20 3 / # $ #
62 # $
2 3 8 * + #
4 48 4 2 + / #
SUM # $
1 2 3 4 5 #
R #
@
...where "@" d
On Tuesday, 21 April 2015 at 02:04:24 UTC, TheGag96 wrote:
It'll just leave some trailing whitespace, which I don't want.
oh it also keeps the newlines attached. Blargh.
Well, forget the D functions, just use the C functions:
import core.stdc.stdio;
void main() {
char[16] token;
On Tuesday, 21 April 2015 at 01:46:53 UTC, Adam D. Ruppe wrote:
I think this should work:
import std.stdio;
void main() {
string token;
while(readf("%s ", &token))
writeln(token);
}
Have you tried that? What is wrong with it if you have?
It'll just leave some
I think this should work:
import std.stdio;
void main() {
string token;
while(readf("%s ", &token))
writeln(token);
}
Have you tried that? What is wrong with it if you have?
Hi guys! I had this homework assignment for data structures that
has a pretty easy solution in C++. Reading input like this...
1 2 3 # $
4 3 * ! #
20 3 / # $ #
62 # $
2 3 8 * + #
4 48 4 2 + / #
SUM # $
1 2 3 4 5 #
R #
@
...where "@" denotes the end of input is fairly simple in C++:
string toke
