Re: RefRange behavior

On Wednesday, 14 March 2018 at 10:22:45 UTC, Alex wrote: Is there a simple workaround, maybe? ok, the workaround would be to enumerate the member and to use the former notation.

RefRange behavior

Hi all, given this: ´´´ import std.range; size_t[] arr; struct S { RefRange!(size_t[]) member; } void fun(ref size_t numByRef){} void main() { arr.length = 42; S s; s.member = refRange(); static assert(__traits(compiles, fun(s.member[0])));