On 1/26/22 18:49, Andrey Zherikov wrote:
> I want something like this:
> ```d
> void foo(MODULES... = __MODULE__)() {}
Two other options:
1)
void foo(MODULES_...)() {
static if (MODULES_.length == 0) {
import std.meta : AliasSeq;
alias MODULES = AliasSeq!__MODULE__;
} else {
a
On 1/27/22 10:21 AM, Andrey Zherikov wrote:
So is it possible to get rid of the alias?
I'm not sure it's worth the effort? Yours is a pretty straightforward
solution.
-Steve
On Thursday, 27 January 2022 at 03:19:59 UTC, Jaime wrote:
You can accomplish this by heading off the template sequence
parameter with several default template parameters. If you need
them all under one name, you can recombine them in the function
body with std.meta.AliasSeq, the effective "kin
On Thursday, 27 January 2022 at 02:49:22 UTC, Andrey Zherikov
wrote:
What is the best way to emulate a default value for template
sequence parameter of a function?
I want something like this:
```d
void foo(MODULES... = __MODULE__)() {}
// these should work:
foo!(module1, module2);
foo!(module1
What is the best way to emulate a default value for template
sequence parameter of a function?
I want something like this:
```d
void foo(MODULES... = __MODULE__)() {}
// these should work:
foo!(module1, module2);
foo!(module1);
foo(); // this should use current module (__MODULE__)
acc
