On Thursday, 10 September 2020 at 13:06:41 UTC, Joseph Rushton
Wakeling wrote:
`hasUDA!(T, AnotherUDA)`
...do you have to use hasUDA?
The language works with class UDAs, but hasUDA doesn't support it.
If you write your own test function though you can:
``import std.traits;
class BaseUDA {
On Thursday, 10 September 2020 at 13:14:47 UTC, drug wrote:
Just a thought - couldn't you use classes for this? Get an UDA
and check if it is a descendant of the specific class.
Yes, I did wonder about that, but it doesn't allow all the
inference that I'm looking for. For example:
class
On 9/10/20 4:06 PM, Joseph Rushton Wakeling wrote:
Hello folks,
Is there any way to define UDAs such that they automatically inherit
other UDA definitions?
For example, suppose I define:
enum BaseUDA { A, B }
Is there a way to define `AnotherUDA` such that if `hasUDA!(T,
AnotherUDA)`
Hello folks,
Is there any way to define UDAs such that they automatically
inherit other UDA definitions?
For example, suppose I define:
enum BaseUDA { A, B }
Is there a way to define `AnotherUDA` such that if `hasUDA!(T,
AnotherUDA)` then it is a given that `hasUDA!(T, BaseUDA)` will
a
