On Wednesday, 20 July 2016 at 08:01:01 UTC, Lodovico Giaretta
wrote:
Note that void is a type, while S is not. So you can do:
assert(is(void)) // is(type) returns true
assert(!is(S)) // is(template) returns false;
Thanks very much. I should have noticed this before. T.T
On Wednesday, 20 July 2016 at 05:54:41 UTC, mogu wrote:
On Wednesday, 20 July 2016 at 01:50:37 UTC, Adam D. Ruppe wrote:
On Wednesday, 20 July 2016 at 01:14:05 UTC, mogu wrote:
Why S's type isn't something like `S: (T) -> S`?
Because S isn't a type... think of a template as being like a
On Wednesday, 20 July 2016 at 01:50:37 UTC, Adam D. Ruppe wrote:
On Wednesday, 20 July 2016 at 01:14:05 UTC, mogu wrote:
Why S's type isn't something like `S: (T) -> S`?
Because S isn't a type... think of a template as being like a
function that returns a type.
int foo(int) { return 0; }
On Wednesday, 20 July 2016 at 01:14:05 UTC, mogu wrote:
Why S's type isn't something like `S: (T) -> S`?
Because S isn't a type... think of a template as being like a
function that returns a type.
int foo(int) { return 0; }
There, you wouldn't expect typeof(foo) to be int, no, typeof(foo)
```
struct S(T) {}
static assert(is (typeof(S) == void));
```
Why S's type isn't something like `S: (T) -> S`?
