On Saturday, 3 November 2018 at 21:13:49 UTC, Jonathan M Davis
wrote:
There's a continue right above the default case. So, if the
code hits that point, it will loop back to the top.
- Jonathan M Davis
There's also the benefit that FLAGS f exists only until the end
of the loop, and thus
Thankyou.
As the great Gump's mother said, stupid is as stupid does.
On Saturday, 3 November 2018 at 21:03:16 UTC, Venkat wrote:
The last break statement prevents the loop from returned for a
second iteration. Then why use a while ?
The continue statement may abort the current iteration and start
the next, causing the final break to not necessarily be executed
On Saturday, November 3, 2018 3:03:16 PM MDT Venkat via Digitalmars-d-learn
wrote:
> while (1)
> {
> FLAGS f;
> switch (*p)
> {
> case 'U':
> case 'u':
> f = FLAGS.unsigned;
> goto
while (1)
{
FLAGS f;
switch (*p)
{
case 'U':
case 'u':
f = FLAGS.unsigned;
goto L1;
case 'l':
f = FLAGS.long_;
error("lower case integer suffix
