This is going to sound stupid, but how do you have two pointers'
targets copy each other? since pointers are used like reference
types, how do you write the C++ equivalent of *p1 == *p2
Here is the context of what I'm trying to do:
struct S
{
struct Payload
{}
Payload payload;
On 07/27/12 18:11, monarch_dodra wrote:
This is going to sound stupid, but how do you have two pointers' targets copy
each other? since pointers are used like reference types, how do you write
the C++ equivalent of *p1 == *p2
Exactly the same, there's no difference between C and D pointers,
On Friday, 27 July 2012 at 16:47:47 UTC, Artur Skawina wrote:
On 07/27/12 18:11, monarch_dodra wrote:
This is going to sound stupid, but how do you have two
pointers' targets copy each other? since pointers are used
like reference types, how do you write the C++ equivalent of
*p1 == *p2
On 07/27/2012 09:11 AM, monarch_dodra wrote:
This is going to sound stupid, but how do you have two pointers' targets
copy each other? since pointers are used like reference types, how do
you write the C++ equivalent of *p1 == *p2
The type must provide a function to make a copy of itself.
On Fri, 27 Jul 2012 19:28:06 +0200, monarch_dodra monarchdo...@gmail.com
wrote:
I'm kind of confused, because every time I see pointer usage, the
deference operator is omitted?
For example:
struct S
{
void foo(){};
}
S* p = new S();
p.foo();
When and where
On Friday, July 27, 2012 10:32:07 Ali Çehreli wrote:
On 07/27/2012 09:11 AM, monarch_dodra wrote:
This is going to sound stupid, but how do you have two pointers' targets
copy each other? since pointers are used like reference types, how do
you write the C++ equivalent of *p1 == *p2
On 07/27/12 19:28, monarch_dodra wrote:
On Friday, 27 July 2012 at 16:47:47 UTC, Artur Skawina wrote:
On 07/27/12 18:11, monarch_dodra wrote:
This is going to sound stupid, but how do you have two pointers' targets
copy each other? since pointers are used like reference types, how do you
