){return
funImpl(theta,a,b,c);
bool fun(double theta){return funImpl(theta);}
2. Would it make sense to have 'out default argument of void' in D?
void initializer means uninitialized. I don't think that can do what you
want.
On 01/04/2012 02:19 PM, Caligo wrote:
I have a function that looks something like this:
bool fun(double theta, out A a, out B b, out C c){ /* ... */ }
if fun() returns false, then nothing is supposed to be assigned to a,
b, c. If it returns true, then values are assigned to a, b, c.
On Wed, Jan 4, 2012 at 4:40 PM, Jesse Phillips
jessekphillip...@gmail.com wrote:
Out parameters are initialized. The declaration you want is:
bool fun(double theta, A a = A.init, B b = B.init, C c = C.init){ /* ... */
}
In my case A, B, and C are structs, so that works the way I wanted it.
On Wednesday, 4 January 2012 at 23:02:24 UTC, Simen Kjærås
wrote:
On Wed, 04 Jan 2012 23:40:28 +0100, Jesse Phillips
jessekphillip...@gmail.com wrote:
On Wednesday, 4 January 2012 at 22:19:28 UTC, Caligo wrote:
1. Are there any other solutions ?
2. Would it make sense to have 'out default
