https://github.com/Hackerpilot/libdparse/blob/master/src/std/d/lexer.d#L1491
Of course consuming it dchar by dchar also works:
string s = `\tabŁŃ\r\nx`;
assert(parseDchar(s) == '\t');
assert(parseDchar(s) == 'a');
assert(parseDchar(s) == 'b');
assert(parseDchar(s) == 'Ł');
assert(parseDchar(s) == 'Ń');
assert(parseDchar(s) == '\r');
assert(
On 2015-02-09 at 03:40, Timothee Cour via Digitalmars-d-learn wrote:
Is there a simple way to parse a string as a char?
eg:
unittest{
assert(parseChar(`a`)=='a');
assert(parseChar(`\n`)=='\n'); //NOTE: I'm looking at `\n` not "\n"
// should also work with other forms of characters, see
On 9/02/2015 3:40 p.m., Timothee Cour via Digitalmars-d-learn wrote:
Is there a simple way to parse a string as a char?
eg:
unittest{
assert(parseChar(`a`)=='a');
assert(parseChar(`\n`)=='\n'); //NOTE: I'm looking at `\n` not "\n"
// should also work with other forms of characters, see
h
Is there a simple way to parse a string as a char?
eg:
unittest{
assert(parseChar(`a`)=='a');
assert(parseChar(`\n`)=='\n'); //NOTE: I'm looking at `\n` not "\n"
// should also work with other forms of characters, see
http://dlang.org/lex.html
}
Note, std.conv.to doesn't work (`\n`.to!char do
