== Quote from Jacob Carlborg (d...@me.com)'s article
> On 2010-08-06 15:33, Pluto wrote:
> > == Quote from Steven Schveighoffer (schvei...@yahoo.com)'s article
> >> On Fri, 06 Aug 2010 08:51:31 -0400, Pluto wrote:
> >>> Are these equivalent?
> >>>
> >>> S s;//struct
> >>>
> >>> void f(ref S s){s.x
On 2010-08-06 15:33, Pluto wrote:
== Quote from Steven Schveighoffer (schvei...@yahoo.com)'s article
On Fri, 06 Aug 2010 08:51:31 -0400, Pluto wrote:
Are these equivalent?
S s;//struct
void f(ref S s){s.x++;}
f(s);
void f2(S* s){(*s).x++;}
f2(&s);
They are pretty much equivalent. I think
== Quote from Steven Schveighoffer (schvei...@yahoo.com)'s article
> On Fri, 06 Aug 2010 08:51:31 -0400, Pluto wrote:
> > Are these equivalent?
> >
> > S s;//struct
> >
> > void f(ref S s){s.x++;}
> > f(s);
> >
> > void f2(S* s){(*s).x++;}
> > f2(&s);
> They are pretty much equivalent. I think th
== Quote from Steven Schveighoffer (schvei...@yahoo.com)'s article
> On Fri, 06 Aug 2010 08:51:31 -0400, Pluto wrote:
> > Are these equivalent?
> >
> > S s;//struct
> >
> > void f(ref S s){s.x++;}
> > f(s);
> >
> > void f2(S* s){(*s).x++;}
> > f2(&s);
> They are pretty much equivalent. I think th
On Fri, 06 Aug 2010 08:51:31 -0400, Pluto wrote:
Are these equivalent?
S s;//struct
void f(ref S s){s.x++;}
f(s);
void f2(S* s){(*s).x++;}
f2(&s);
They are pretty much equivalent. I think the code generated actually will
be exactly the same. However, the compiler treats ref differently
Are these equivalent?
S s;//struct
void f(ref S s){s.x++;}
f(s);
void f2(S* s){(*s).x++;}
f2(&s);
If so, why is it stated that ref is very rarely used?
It looks like something I would use a lot with structures.
