14.02.2011 18:06, Charles McAnany пишет:
Hi, all. So I'm new to this whole contract thing. (I'm coming from C and Java.)
I got the impression that using foo(out arg) means that arg is given its
default value, but other than that it's just like ref. So, here's the basic
code I have thus far.
01 i
Charles McAnany Wrote:
> Hi, all. So I'm new to this whole contract thing. (I'm coming from C and
> Java.)
> I got the impression that using foo(out arg) means that arg is given its
> default value, but other than that it's just like ref. So, here's the basic
> code I have thus far.
The init val
Hi, all. So I'm new to this whole contract thing. (I'm coming from C and Java.)
I got the impression that using foo(out arg) means that arg is given its
default value, but other than that it's just like ref. So, here's the basic
code I have thus far.
01 import std.random:Random;
02 import std.cont
