I have found the documentation for each in std.algorithm a bit
terse. It seemed like it was an eager version of map, but it
seems to be a bit more limited than that.
In particular, the documentation says that if you can mutate the
value in place, then you can call each on it. The first thing
On Monday, 20 July 2015 at 14:40:59 UTC, jmh530 wrote:
I have found the documentation for each in std.algorithm a bit
terse. It seemed like it was an eager version of map, but it
seems to be a bit more limited than that.
In particular, the documentation says that if you can mutate
the value
On Monday, 20 July 2015 at 14:40:59 UTC, jmh530 wrote:
Is there a way to write a void lambda that would work with each?
Ugh, I hate that I can't edit posts. I meant to delete this line.
On Monday, 20 July 2015 at 15:08:16 UTC, Nicholas Wilson wrote:
But the lambda takes a ref parameter...
Yes, but it never writes to it:
x.each!((ref a) = a + 1);
Instead, this should work:
x.each!((ref a) = a = a + 1);
... as a short-hand for:
x.each!((ref a) { a = a + 1; });
On Monday, 20 July 2015 at 15:12:28 UTC, Marc Schütz wrote:
On Monday, 20 July 2015 at 15:08:16 UTC, Nicholas Wilson wrote:
But the lambda takes a ref parameter...
Yes, but it never writes to it:
x.each!((ref a) = a + 1);
Instead, this should work:
x.each!((ref a) = a = a + 1);
On Monday, 20 July 2015 at 14:40:59 UTC, jmh530 wrote:
I have found the documentation for each in std.algorithm a bit
terse. It seemed like it was an eager version of map, but it
seems to be a bit more limited than that.
In particular, the documentation says that if you can mutate
the value
On Monday, 20 July 2015 at 14:59:21 UTC, John Colvin wrote:
On Monday, 20 July 2015 at 14:40:59 UTC, jmh530 wrote:
[...]
Everything is exactly as I would expect. Lambdas with = are
just shorthand that skips the return expression and
std.algorithm.each just calls the lambda for each element
Also, map is lazy, but each isn't.
On Monday, 20 July 2015 at 14:40:59 UTC, jmh530 wrote:
I have found the documentation for each in std.algorithm a bit
terse. It seemed like it was an eager version of map, but it
seems to be a bit more limited than that.
Why are you trying to use `each` in place which belongs to `map`?
On Monday, 20 July 2015 at 21:24:37 UTC, sigod wrote:
On Monday, 20 July 2015 at 14:40:59 UTC, jmh530 wrote:
I have found the documentation for each in std.algorithm a bit
terse. It seemed like it was an eager version of map, but it
seems to be a bit more limited than that.
Why are you
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