Jake,
Sorry, I have commented out the console.debug() messages. I will convert
the code over to $.log() when I get a chance.
I'm using the console.debug() in FF2 and firebug 1.0b9
-Steve
Ⓙⓐⓚⓔ wrote:
> your console.debug("button: action:"+ e.data.action +"
> check_dirty:"+check_dirty);
>
> sto
your console.debug("button: action:"+ e.data.action +"
check_dirty:"+check_dirty);
stops my firefox in it's tracks! I use
jQuery.fn.debug = function(message) {
return this.log('debug:' + (message || '')
+"[").each(function(){jQuery.log(this);}).log("]");
}
jQuery.fn.log = jQuery.log = func
Stephen Woodbridge wrote:
> Hi all,
>
> I know there has got to be an easy way to do thing but I'm having
> trouble figuring it out.
>
> I have a div that has an image in it and this image is positioned
> relative to the div based on what I want to look at and this works great
> so far.
>
> N
