#26524: Django Admin list_display - Unable to display foreign key id
-------------------------------+-------------------------------------------
Reporter: cristianocca | Owner: nobody
Type: Bug | Status: new
Component: contrib.admin | Version: 1.9
Severity: Normal | Keywords: admin list_display changelist
Triage Stage: Unreviewed | Has patch: 0
Easy pickings: 0 | UI/UX: 0
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Given these two models.
{{{
class A(models.Model):
name = models.CharField(max_length=100)
def __unicode__(self):
return self.name
class B(models.Model):
name = models.CharField(max_length=100)
fk = models.ForeignKey(A)
def __unicode__(self):
return self.name
}}}
And these model admin
{{{
class AAdmin(admin.ModelAdmin):
list_display = ('id','name')
admin.site.register(A, AAdmin)
class BAdmin(admin.ModelAdmin):
list_display = ('id','name','fk_id','fk')
admin.site.register(B, BAdmin)
}}}
As you see, for BAdmin I'm trying to display the actual id of the foreign
key, so I prevent an additional unwanted join (or worse, one query per
related object if no select related is added). However, the admin page
refuses to display the id and instead renders the whole object (calling
the __unicode__ method) which causes the additional join I don't want.
In order to demostrate it I also added the 'fk' relation which works as
expected
The change list result is then
{{{
1 test B test A test A
}}}
where it should be
{{{
1 test B 1 test A
}}}
In order to work around it, I can define a callable that just returns the
id property, but that's terrible because I lose any sort option on it plus
I need to write quite a few more lines.
--
Ticket URL: <https://code.djangoproject.com/ticket/26524>
Django <https://code.djangoproject.com/>
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