I am new in Django
Please share any simple Django application source code with AJAX
support, for reference.
I am planing to develop an account managing web application in Django.
If any one have source code of account managing web application in
Django, please share with me for reference.
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You
On Fri, Nov 13, 2009 at 11:42 PM, neridaj wrote:
> I'm using django-tagging and I think it's causing an error when I try
> to access the admin page. If I comment out the urls that reference
> django-tagging views the error goes away.
>
> from django.conf.urls.defaults import *
> from blog.models
Dear all,
What I need is a view only django admin. Asking on the channel, people
there have suggested databrowse, which is great and all but my
requirements is that I need a search similar to what is in django
admin. Thinking about it all I need is the django admin object list
with the ability to
I don't know for auth... neither sites... But to disable stuff from admin
you just:
admin.site.unregister(TheTargetModel)
on urls.py
[]
2009/11/15 Zeynel
>
> Is it possible to remove "Auth" and "Sites" sections from the Admin
> panel?
>
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Oops, sorry about that. Here is the error:
TemplateSyntaxError at /admin/
Caught an exception while rendering: 'str' object is not callable
admin/base.html, error at line 30
30 {% url django-admindocs-docroot as docsroot %}
On Nov 14, 1:47 am, Daniel Roseman wrote:
> On Nov 14, 4:42 am, n
Is it possible to remove "Auth" and "Sites" sections from the Admin
panel?
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Hi,
In my apps, Users of the app participate in a certain Year. I would
like a Year to continue a ManyToOne relationship with a User. As
creating a ForeignKey on a User is not possible, what would be the
best way to do this? I don't need a full-blown profile for a user,
just this connection with a
On 14 Lis, 23:20, Nagy Károly wrote:
> Please help me in orm level filtering many-to-many relations.
>
> I have to filter all "authors" who does not belongs to any "articles".
> Or the opposite of this, list of orphaned articles...
>
> I dont want to write sql in the model if possible.
How abou
Please help me in orm level filtering many-to-many relations.
I have to filter all "authors" who does not belongs to any "articles".
Or the opposite of this, list of orphaned articles...
I dont want to write sql in the model if possible.
Thank you,
Charlie.
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Has anyone tried the Mediatemple/Django grid component? Does it work
nice?
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django-
I'm using the django.contrib.comments app in Django 1.1 and would
really like to be able to enter contents for objects while editing
them in the admin interface. Specifically, I have a Member model
which represents a person who is a member of an organization and want
users of the admin interface t
they are in there though?
Now i'm getting a diff error
On Nov 14, 2:27 pm, Carlos Ricardo Santos
wrote:
> I can only see that you're missing the
> templates_path/blog/post_archive_day.html
> template.
>
> 2009/11/14 Bobby Roberts
>
>
>
> > anyone know what this traceback means?
>
> >http://www.
I can only see that you're missing the
templates_path/blog/post_archive_day.html
template.
2009/11/14 Bobby Roberts
> anyone know what this traceback means?
>
>
> http://www.thecigarcastle.com/blog/2009/nov/1/my-first-blog-post/
>
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anyone know what this traceback means?
http://www.thecigarcastle.com/blog/2009/nov/1/my-first-blog-post/
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Thanks for the help, Karen, Solved :D
Django is really so simple... I just keep thinking it has limits... The
limit is only the mind.
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Karen's way:
*User.objects.filter( profile__paid='N' )* #works great!
Or even another way I found now:
*profiles= UserProfile.objects.
On Sat, Nov 14, 2009 at 11:21 AM, Carlos Ricardo Santos <
carlosricardosan...@gmail.com> wrote:
> Hi,
>
> I extended the user class with a UserProfile, with the Django docs
> tutorial.
> But now I need to do a query to list all users that haven't payed
> (pay='No').
>
>
> I tried something like th
Hi,
I extended the user class with a UserProfile, with the Django docs tutorial.
But now I need to do a query to list all users that haven't payed
(pay='No').
I tried something like this: *User.objects.filter(
User.get_profile().paid='No' )*
or *User.objects.filter( User.profile.paid='No' )*
Bu
I guess the answer depends on what you mean by "integrate." If you
have both written parts that serve html pages, just setup apache
configs so that part of the urls are routed to django and the other
urls are routed to php.
Another way to integrate would be by setting up one of the installs as
an
It looks interesting, especially GoogleAnalyticsMiddleware.
On Nov 6, 2:29 pm, Johan wrote:
> Is anybody using django-tracking (http://code.google.com/p/django-
> tracking/) and if so is it any good ? Is there any other applications
> that does this type of logging?
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On Sat, Nov 14, 2009 at 10:25 AM, Denis Bahati wrote:
> Hi,
> Here is my model am using to update items status.
>
> class User(models.Model)
> users = models.ForeignKey(User)
> resources = models.ForeignKey(Resource)
>date_tracked = models.DateTimeField('Date T
I figured that "active" and "staff" need to be checked as explained
here:
http://docs.djangoproject.com/en/dev/faq/admin/
Does anybody know how to make admin "view only" for a user? This
paragraph from the above appears to explain a similar process:
How do I limit admin access so that objects ca
I have two SQL functions that I'd like to use in Django. They both
work no problem if I paste them into psql (PostgreSQL's shell). As I
have the same problem with both, I'll just post and explain the
simpler one. It looks like this:
CREATE OR REPLACE FUNCTION skater_name_match(INTEGER,VARCHAR)
RET
Hi,
Here is my model am using to update items status.
class User(models.Model)
users = models.ForeignKey(User)
resources = models.ForeignKey(Resource)
date_tracked = models.DateTimeField('Date Tracked')
description = models.TextField()
statu
On Sat, Nov 14, 2009 at 9:47 AM, Bobby Roberts wrote:
> Specifically, why doesn't Definition show up as a text area in /admin:
>
>
It does when I cut and paste your defs into a test project. Thus there
doesn't seem to be anything wrong with the code you posted, so your seeing
different results i
As GeoDjango is now integrated into Django framework, it should be
able to recognize GeoDjango models.
But, as soon as I add "from django.contrib.gis.db import models"
instead of "from django.db import models", Django stops recognizing
the app and gives this error:
Error: App with label locat
I have the same problem as soon as I add "from django.contrib.gis
import models" instead of "from django.db import models", the "sqlall"
command gives this error:
Error: App with label location could not be found. Are you sure your
INSTALLED_APPS setting is correct?
As soon as I add "from django.d
Specifically, why doesn't Definition show up as a text area in /admin:
class DictionAid (models.Model):
Id = models.AutoField(primary_key=True)
Term = models.CharField (max_length=50, blank=False,
db_index=True)
Definition = models.TextField (max_length=1000, blank=False)
Hello,
I am creating a new user successfully but I cannot login with that new
user. I make sure that username and pw (case sensitive) are correct.
Is there more to creating a new user?
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You might want to do a search on django-tagging. this has been done
and done well.
On Nov 13, 6:04 pm, Continuation wrote:
> How do I do queries when ContentType is involved?
>
> Using the example in the doc
> (http://docs.djangoproject.com/en/dev/ref/contrib/contenttypes/#id1
> )
>
> class Tagg
The problem is not in templates. Probably either a view or a template
tag does something wrong to the caption string. If Django hides the
traceback, try testing each module separately. The simplest way to
evade the "raise wrapped" is to raise an exception right _before_
rendering data prepared by y
I have got tracks working with the extra() function. I do the
following:
tracks.extra(select={'owned':'SELECT Count(*) FROM shop_track_owners
WHERE track_id=shop_track.id and user_id='+str(user.id)})
This works great for tracks. However, how will I do this when I'm just
passing a queryset of albu
Great, thank you. When I ran it in the command prompt it worked fine.
I noticed that the first column needs to be "pk" with rows starting
with integers.
On Nov 13, 11:24 pm, Karen Tracey wrote:
> On Fri, Nov 13, 2009 at 10:57 PM, Zeynel wrote:
> > Thanks, I tried but this did not work either:
>
On Nov 14, 4:42 am, neridaj wrote:
> I'm using django-tagging and I think it's causing an error when I try
> to access the admin page. If I comment out the urls that reference
> django-tagging views the error goes away.
>
> from django.conf.urls.defaults import *
> from blog.models import Entry, L
On Nov 14, 12:04 am, Continuation wrote:
> How do I do queries when ContentType is involved?
>
> Using the example in the doc
> (http://docs.djangoproject.com/en/dev/ref/contrib/contenttypes/#id1
> )
>
> class TaggedItem(models.Model):
> tag = models.SlugField()
> content_type = models.Fo
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