Oh yeah, see Tim's answer to your duplicate post.
-James
On May 27, 2015 6:05 PM, "James Schneider" wrote:
> Do you have a /static directory on your server? Does your user have write
> privileges to it? I suspect you are trying to copy to a local directory in
> your
Do you have a /static directory on your server? Does your user have write
privileges to it? I suspect you are trying to copy to a local directory in
your project named static, and not one located at the root of your file
system, so you probably need to change where your static files point.
-James
STATIC_ROOT should be the absolute path to the directory static files
should be collected to. Example: "/var/www/example.com/static/"
It looks like you set it to "/static" which probably doesn't exist (or at
least your user doesn't have write privileges to it).
On Wednesday, May 27, 2015 at
Hi Abraham,
I guess my advantage is that my applications are quite tightly coupled,
so I can set some flags in settings.py.
The key point is that I'm importing class instance from my API code. That
instance represents either the real endpoint or mocked endpoint based on
some flags in
How can we solve this problem? copying admin static files to STATIC_ROOT
may solve this .But how
(hackernews)junkuos@ hackernews$ ./manage.py collectstatic
You have requested to collect static files at the destination
location as specified in your settings:
/static
This will overwrite
i am using ubntu14.04 copying admin static files to STATC_ROOT may solve
this problem but how can i run this command successfully?
(hackernews)junkuos@ hackernews$ ./manage.py collectstatic
You have requested to collect static files at the destination
location as specified in your settings:
Does not work, why? remember, we need get each form inline guided on
the next line
self.initial = [{'attribute': attribute} for attribute in obj.category.
attributes.all()]
# Important: This start each form with a different value, [{'attribute':
'Colors'}, {'attribute': 'Sizes'}, ..]
if
Hello All,
I am currently extending the existing User model to store additional
information. So, basically I have:
# models.py
class Person(models.Model):
user = models.OneToOneField(User, verbose_name=_('User'))
zipcode = models.CharField(_('Zip Code'), max_length=9, blank=True,
Hmm. Sorry, I think that I sent the download link when I intended the web
link. The trailing ".git" made things bad.
Try https://gist.github.com/vernondcole/9adedbab1899224a4eaf
On Tuesday, May 26, 2015 at 4:51:59 AM UTC-6, aRkadeFR wrote:
>
> Thanks for the email on the django-user ML.
>
>
Hello Jirka,
That's right. I'd forgotten that the settings.py could be used to
initialize something like this! (facepalm!) But since you mentioned it, ..
how would you initialize (or call mock_setup()) from your app or model? I
can't recollect any entry point which can be used.
-Abraham V.
>
> Just in general, is it a good idea to expose primary keys like this?
> sometimes you can see them in urls too, like: www.yoursite/blog/1/, 1
> would be the primary key of a blog.
It's an easy way to refer to an object. Unless there is a secure connection
it's this is IMHO the best way to
Thank you! Yes, I forgot about the csrf. You are right, it would be
difficult to fake the CSRF string.
Just in general, is it a good idea to expose primary keys like this?
sometimes you can see them in urls too, like: www.yoursite/blog/1/, 1
would be the primary key of a blog.
On Wednesday,
Without looking at the link I guess that you explantion is more or less
correct.
But it's not a security issue that the database is updated by a form. It
has to be updated by a form. To make it a correct django form there is a
hidden field with the CSRF token. This protects the database being
Hello,
I have a formset and when I render it, Django would include this line in
the HTML:
I am curious what is the purpose of having an id field here.
I mean in what situation would you use it. I did look through Django's
documentation
on formset
Think I got it now.
Can you see if this stackoverflow answer solves your problem:
http://stackoverflow.com/questions/5329586/django-modelchoicefield-filtering-query-set-and-setting-default-value-as-an-obj
On Wed, May 27, 2015 at 9:41 AM, Felipe wrote:
> Hello, Filipe Ximenes,
Hello, Filipe Ximenes, in fact it is not so difficult. To avoid using ajax,
what I do is initialize each form inline with a default value. Few
ATTRIBUTES has verified and initialize no possibility that the fronentd
they can edit. All right up here, but the problem is that for each
attribute
Russ,
I have a view which create a new thread to process files user uploaded. I
found either InMemoryUploadedFile or TempUploaedFile is closed in the new
thread. I think that might be caused by the exit of the view thread. Do you
have any idea how to re-open the closed UploadedFile or clone
>From what I could understand, you want to change the options of the "value
options" field depending on the selected "attribute".
Since the choosing of the "attribute" happens in the frontend and there's
no page refresh, the backend does not know about it, and therefore cannot
filter the "value
In this case the problem comes if the user also filled the other ~60
non-approved fields and has to start over, which makes this approach a
no-go for me :(
2015-05-27 10:25 GMT+02:00 James Schneider :
> If you are able to catch the validation error, then perhaps you can
If you are able to catch the validation error, then perhaps you can
redirect users back to the original form URL (since the form should have
the new correct values on the next load).
Check out the form.invalid() when working with the form directly or
form_invalid() for CBV's. If you catch that
Hello,
although the data is from the database, the form itself is not a ModelForm
derivative. Also, this code you suggest will only modify the model handling
part of the form, thus, the user will see a value he entered, although the
database holds a different one.
Best,
Gergely
2015-05-27 9:16
Hey,
Look at the widgets in the fields forms:
https://docs.djangoproject.com/en/1.8/ref/forms/widgets/
Implement your own widget, so it includes the javascript
and the css your datepicker needs.
Then render it in your template (the medias included).
Have a good one
On 05/26/2015 07:30 PM,
Hi,
Maybe you can solve this in the views.py with commit=False
https://docs.djangoproject.com/en/1.8/topics/forms/modelforms/
And from here you can render the new form with the initial data
# Create a form instance with POST data.>>> f = AuthorForm(request.POST)
# Create, but don't save the
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