Some one there can answer!?
On Sunday, 20 May 2012 13:12:17 UTC+5:30, Aditya Sriram M wrote:
>
> Ooo.. Nice.
>
> Hmm.. I tried this but it failed? Can you pls correct me?
>
> def queryset(self, request):
> result = super(CustomerAdmin,
> self).queryset(r
I too have a similar issue. Any workarounds to achieve this...
On Saturday, 16 December 2006 09:52:39 UTC+5:30, Dan wrote:
>
> I'd like to represent foreign key relationships inside the Admin
> interface when there are multiple nested one-to-many relationships.
> Here's a simple example model to d
Help please! :-|
On Saturday, 19 May 2012 18:31:05 UTC+5:30, Aditya Sriram M wrote:
>
> I have a function like this..
>
> list_display = (..,get_link_to_users, ..)
>
>def get_link_to_users(self, obj):
> html_table = ' href="JavaScript:window.open
easier, but only
> follows an fk in one direction.
>
> Matt.
>
> On Sunday, May 20, 2012 12:27:57 AM UTC+9:30, Aditya Sriram M wrote:
>>
>> Hi,
>>
>> again, my models are Customer, Users and Devices.
>>
>> I would like to search by Customer and
Hi,
again, my models are Customer, Users and Devices.
I would like to search by Customer and retrieve all 'select_related' rows
of all the three models.
Eg. like this..
Customer1 User1 Device1
Customer1 User1 Device2
Customer1 User2 Device1
Customer1 User2 Device2
etc etc..
Is this possible in
I have an admin site with two models, Customer and Users with one-to-many
relationship.
Now when I display the customer in admin site, I wanted to display it's
Users in a table format. Basic HTML formatted table works fine but its too
rugged and not very attractive.
Note: I do this by manually
I have a function like this..
list_display = (..,get_link_to_users, ..)
def get_link_to_users(self, obj):
html_table = '
My Users ' % (obj.customer_id)
print html_table
return html_table
get_link_to_fortress_users.short_description = 'Fortress Users'
get_link_t
t sure if this is what you look for, and I am not sure if
> allow_tags is needed
>
>
>
>
> On Monday, May 7, 2012 12:41:59 PM UTC+2, Aditya Sriram M wrote:
>>
>> Hi All,
>>
>> I could successfully try the Django framework on my Oracle DB. I never
>&
Hi All,
I could successfully try the Django framework on my Oracle DB. I never
thought programming would be this easy!!!
Thanks for the wonderful framework.
Now, I want to have an Admin Site with 'another such admin site in its
row'. Is it possible?
Example: Take the models Customers, Users an
My models:
*
*
>
> *# models.py
> class Model1(models.Model):
> pk = models.BigIntegerField(primary_key=True)
> col1 = models.IntegerField()
> class Model2(models.Model):
> fk = models.ForeignKey(Model1)
> col1 = models.CharField(max_length=255)
> # admin.py
> class Model1Admin(adm
Okay!! My bad.. was using the wrong function to fetch. Use fetchone()
instead.
On Tuesday, 1 May 2012 07:22:11 UTC+5:30, Aditya Sriram M wrote:
>
>
> I have been trying a lot but could not make out why it happens,
>
> class FortressUserAdmin(admin.ModelAdmin):
I have been trying a lot but could not make out why it happens,
class FortressUserAdmin(admin.ModelAdmin):
list_display(. . . , get_my_schema)
def get_my_schema(self, obj):
sql_query = "select prop_val from customer_property where customer_id = %d
and property_value like 'SCHEM
2012 21:30:41 UTC+5:30, akaariai wrote:
>
> On Apr 22, 1:31 pm, Aditya Sriram M wrote:
> > File myapp/models.py has this sample code..
> >
> > from django.db import models
> >
> > # model for 'user' table in database or
File myapp/models.py has this sample code..
from django.db import models
# model for 'user' table in database oracle_dbuser1:user
class User(models.Model):
. . .
customerid = models.BigIntegerField()
# model for 'customer' table in database oracle_dbuser2:customer
# Note that there is
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