#x27;)
>
> will return an unicode string, u"public_html", instead of a normal
> string, 'public_html'.
>
>
> If it works with the byte string, try changing the line to
>
> subdir_path = str(request.GET.get('subdir'))
>
> Nuno
>
> 2010
52AM -0400, Bill Freeman wrote:
> 1. Why is this view code in urls.py?
>
> 2. What is the value of subdir_path in the trace back? (There's a
> little arrow you can click to
> see the variable values fro the frame.)
>
> 2010/4/7 Alexey Vlasov :
> > Hi.
> >
erstand it why "subdir_path" getting the same very value in one case
works perfectly and in the
+other fails.
Django runs following the instuctions
+http://docs.djangoproject.com/en/dev/howto/deployment/fastcgi/#running-django-on-a-shared-hosting-provider-wit
+h-apache
--
BR
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