I've tried different aproach with overriding default save method -
hacking shourtcuts wasn't the best idea.
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Hello
I have following code;
class PlaceForm(ModelForm):
class Meta:
model = Place
exclude = ('useradd',) #excluded, because form shouldn't give
a way to set user manually
Model Place has one foreign key to django User model (useradd)
Is it possible to add field formerly ex
With development server everything works fine (py 2.5), but after
uploading to production server (;y 2.4) I have following error msg.
Traceback (most recent call last):
File "/usr/local/lib/python2.4/site-packages/django/core/handlers/
base.py" in get_response
68. callback, callback_args, callb
> Why not create it there? That is the moment you have all the data you
> need and all you're doing is calling a constructor. The code you've
> written there is a pretty normal pattern for taking form information and
> putting it into a model.
Because it forces me to make different view for each
Thanks for your answer
Now I have following snippet:
http://dpaste.com/11938/
But, is at a good practice to create Model objects in a view ? Where
code of that kind of operations should be placed?
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Hi,
I have 1:n Relation, model A which hase foreign key ("type") to B. I'm
passing foreign key to a view via post using the ModelChoiceField.
Problem is its converted into string, so when I try to create in a
view a 'A' record
like
# data = POST dictionary
A(
address =
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