operations.
I have just released to PyPI an app[1] which, when installed, makes Django 1.8
use the faster mechanisms present in later Django versions. I hope those of
you who are still on 1.8 may find it useful.
Have fun,
Shai.
[1] http://pypi.python.org/pypi/django_18_fast_migrations
all
> the apps are doing reasonable things (monkey patching aside), and django
> shouldn't be calling apps.populate to unpickle a model. Perhaps that is
> unavoidable?
>
The question of whether Django should be calling apps.populate() to
unpickle a model (instance) will
be bett
FYI.
The news as far as Django users are concerned are mostly improved support for
Oracle 12c (not yet used in Django core, but available for users nonetheless)
and some minor bugfixes.
Have fun,
Shai.
-- Forwarded Message --
Subject: cx_Oracle 5.2
Date: Sunday 21
What do you have in models.py for rt_calls?
Did you try passing values that are not 0 or 1?
> On May 20, 2015, at 5:47 PM, Emerson Luiz wrote:
>
> Shai Efrati,
>
> rt.controle is create by in view:
>
> exten = rt_calls.objects.all()
>
> Em quarta-feira, 20 de
5cd5866
>
> Thanks
>
> Em quarta-feira, 20 de maio de 2015 10:55:35 UTC-3, Shai Efrati escreveu:
>>
>> So, when do you expect else? It seems that you don't pass such values.
>>
>> On Wed, May 20, 2015 at 4:52 PM, Emerson Luiz wrote:
>>> Shai Efrati
So, when do you expect *else*? It seems that you don't pass such values.
On Wed, May 20, 2015 at 4:52 PM, Emerson Luiz wrote:
> Shai Efrati,
>
> Thanks for answer...
>
> rt.controle pass always 0 or 1
> I not pass any value.. only 0 or 1
>
> Thanks
>
> Em qua
What does rt.controle hold?
Do you pass any values that are not 0 or 1?
On Wed, May 20, 2015 at 4:37 PM, Emerson Luiz wrote:
> Hi,
>
> I have the following logic:
>
> {% if rt.controle == 1 and rt.Exten|length > 7 %}
> WORK's
> {% elif rt.controle == 1 %}
> WORK's
> {% elif rt.controle == 0 and
sorry.
assuming:
l = [{'key1':'a' , 'key2': 'b'},{'key1':'c' , 'key2': 'd'}]
for e in l:
for k, v in e.iteritems():
print v,
print
On 2/15/15, Shai Efrati wrote:
> assuming:
> l = [{'
assuming:
l = [{'key1':a , 'key2': b},{'key1':c , 'key2': d}]
for e in l:
for k, v in iteritems(e):
print v,
print
On 2/15/15, aronivi...@gmail.com wrote:
> [{'key1':a , 'key2': b},{'key1':c , 'key2': d}]
> a,b
> c,d
>
> --
> You received this message because you are subscribed
the view
name:
class MyUnManagedModel(models.Model):
# ...
# fields
# ...
class Meta:
managed = False
db_table = 'view_name'
Have you run into difficulties?
HTH,
Shai.
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"Dj
setdefault('DJANGO_SETTINGS_MODULE', 'tango.settings')
after from rango.models import...
Let me know if that helped :)
Shai.
On Wed, Oct 1, 2014 at 6:37 PM, Daniel Grace wrote:
> Hi, this is more of a Python question but here is something I don't
> understand in a Django
Hi all,
This release of cx_Oracle includes fixes the segfaults encountered with
Python3, and includes significant performance improvements for 64-bit platforms
(where long is 64-bits, so, specifically, Windows not included).
Strongly recommended for all Oracle users.
Have fun,
Shai
How did you use it in the nav.html file? Can you please write it here,
maybe it's a reference issue.
On Monday, May 5, 2014, Andreas Bloch wrote:
> How do you access (or include) jquery in a file, which is included?
> I'm getting a "Uncaught ReferenceError: $ is not defined" when trying to
> use
It seems to me that your app doesn't knwo where to pull the CSS from.
Can you post your directories structure and your base.html?
Shai.
On Wed, Apr 2, 2014 at 2:45 PM, Warren Jacobus wrote:
> Hi,
>
> I'm having some trouble with my css in my django app. See pic for how
&g
el):
poll = models.ForeignKey(Poll)
choice_text = models.CharField(max_length=200)
votes = models.IntegerField(default=0)
def __unicode__(self):
return self.choice_text
Good luck!
Shai.
On Thu, Mar 27, 2014 at 12:06 PM, Steve Evans <00sev...@gmail.com> wrote:
> Hi I am
Hi Dan,
In the shell, did you re-import your Poll model?
(>>> from polls.models import Poll)
I think you might use a previous version of your model (without the
changes), and that's why it doesn't recognize it.
I might be wrong though :)
Please let me know if it worked.
Hi Errfan,
You can get the SECRET_KEY through the environment variables. Just use:
from os import environ
SECRET_KEY = environ.get('SECRET_KEY')
Good luck!
Shai.
On Tue, Mar 25, 2014 at 8:36 AM, Errfan Wadia wrote:
> Hi,
>
> I am using from django.conf import settings
&g
Thanks for the reply, but that would force me to link each SubForm1
object with both a Form1 & Form2 object. I would like to link them
with either Form1 or Form2
Shai
On Dec 10, 5:22 pm, Superman wrote:
> Can you not create another Field in SubForm 1 model? Like so:
>
> c
return "SubForm1"
Form = models.ForeignKey(Form1)
## some fields here
I would like to have Form2 also be linked to a SubForm1 model. How can
this be done?
Thanks,
Shai
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T
On Aug 4, 2:09 am, Malcolm Tredinnick
wrote:
> On Mon, 2009-08-03 at 17:45 +0300, Shai Berger wrote:
> > Hi all,
>
> > With the new aggregates in django 1.1, I wonder if there's an easy way to
> > aggregate over reverse relationships. As an example, assume a simpl
The question about aggregates still stands -- however, if anybody is wondering
about finding all childless parents, I figured a way:
On Monday 03 August 2009 17:45:18 Shai Berger wrote:
>
> class Team(models.Model):
> name = models.CharField(max_length=100)
>
> class Play
ome obvious way (which I'm currently missing) to solve the
specific problem of finding the empty teams without such aggregates; however,
they do make sense in general.
Is there a way?
Thanks,
Shai.
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