Hello,
Sorry for my amateur question.
I've been stuck on this issue for a while and I can't work out if there is
way I can use my current models to work in this way.
Here is a link to my issue:
Hello
Sorry I am very new to Django and have come across quite the stumbling
block. The details to the issue are in this Stack Overflow post I made a
while ago with no answers:
I'm writing an app where it'd be super helpful for logged-in users from my
company to see error pages and the like as though the app was running with
DEBUG=True, while still preventing ordinary users from seeing that output.
I see that the docs strongly warn me against changing settings at
On Jul 10, 6:03 pm, Chris Rich <[EMAIL PROTECTED]> wrote:
> Hey all,
> So, I'm a beginner here with Django/webdesign/database stuff/all the
> rest of it and I may be getting ahead of myself. I am currently
> getting my feet wet in the Django environment, but I eventually want
> to
I've created a newforms custom form in which I'm trying to update a
user's email while making sure no other user currently has the new
email address. Ignoring the fact that I could use the User generated
forms, I was wondering if anyone could hint on the best way to pass a
variable to a custom
I'd be interested in working with you, e-mail [EMAIL PROTECTED] and
we'll see how I can help.
-- Silas
On Jan 2, 9:23 am, "professorhojo" <[EMAIL PROTECTED]> wrote:
hi all,
we're looking for a part time django developer to work remotely a few
hours here and there, as your
Thanks for the explanation Rajesh.
On Dec 4, 2:31 pm, "RajeshD" <[EMAIL PROTECTED]> wrote:
> On Dec 3, 8:36 pm, "Silas" <[EMAIL PROTECTED]> wrote:
>
> > I have a problem with generic.list_detail.object_list, a limiting
> > queryset, and pagi
I have a problem with generic.list_detail.object_list, a limiting
queryset, and pagination variables.
For some reason when I use the code below, results are restricted to
the sliced 100, but all the pagination variables show results as if the
slice wasn't there.
Example:
{{ pages }} = 12 (not
I figured out what my problem was. It was me being stupid.
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I'm having problems getting Django to work with Apache. Evenything
works with "./manage.py runserver", but I get the errors listed below
when I try to load the project with Apache and mod_python.
I consistently get the same error the first and second refresh,
followed by the "Third+" the rest of
Try just the int() constructor from Python (i.e. int('1') returns 1 as
a integer)
Sincerely,
Silas Snider
On 8/7/06, hotani <[EMAIL PROTECTED]> wrote:
>
> Thanks for the replies.
>
> However, after digging through the documentation I'm not seeing
> anything that will conve
Do they just quote the string? Or do they use a 'bind variable' type idea?
Example:
If an attacker typed
' or 'a'='a
into a password input field for instance, would the ORM properly
prevent the attempted attack from working?
Sincerely,
Silas Snider
On 12/20/05, Adrian
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