hi folks, One of my view's function execute an external application and should return the status of this application's process. This view function should not wait the application end, just execute and return a page that shows application's process. The application sends its status to file and the status page should read it frequently. I made os.spawnv(os.P_NOWAIT, ext.app...) to execute external application but the view function waits until this application to end. If application takes long time, user waits until it ends. Any help would be appreciated.
Thanks in advance Nagi --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
