Is there a way to show or hide a model field in a admin site "change" page
depending upon the value of request.user.is_superuser ?
I was thinking about filling ModelAdmin.field or .fieldset depending on the
value of request.user, but how to read the value of request in ?
Also .readonly_fields when
I think it should be pretty easy to do.
The get_form() method on ModelAdmin returns the form, and it knows
about the current request. So you could modify that to remove the
field after the form is generated.
class MyModelAdmin(admin.ModelAdmin):
def get_form(self, request, obj=None, **kwarg
Thanks for your answer Tim.
def get_form(self, request, obj=None, **kwargs):
form = super(RowModelAdmin, self).get_form(request, obj, **kwargs)
if not request.user.is_superuser:
* **del form['compilatore']*
return form
It seems that the object returned by get_form does not behave like a dict().
Ok I managed to remove the compilatore field from the form (this
RowModelAdmin class is used by many Models, all having the compilatore
field)
def get_form(self, request, obj=None, **kwargs):
form = super(RowModelAdmin, self).get_form(request, obj, **kwargs)
if not request.user.is_superuser:
del
Solved.
It seems this is due to the 1.2 alpha1 bug involving form.is_valid():
http://www.pubbs.net/django/201001/16447/
reverting to django 1.1 solved all my problems
On Wed, Jan 20, 2010 at 10:25, Massimiliano della Rovere <
massimiliano.dellarov...@gmail.com> wrote:
> Ok I managed to remove the
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