Melvyn, thanks for looking at this. Despite my inept attempt at explanation
you've understood what I am trying to do - I need to revisit my
relationships and fully explore my options at the model level.
Thanks again,
Richard
P.S. I'll try to use clearer analogies in the future - in my head the
Hello,
I don't know if you've changed names to protect the innocent, but conceptually,
these
models are hard to translate to the real world. This is the opposite of what
object
oriented programming is trying to accomplish and probably why you're having a
hard
time figuring it out and explain
Building.objects.filter(addresses__street__pk=patientid) will return
all buildings with an address in the same street as the patient. If I
understand correctly, that is :)
2017-01-26 10:41 GMT+01:00 Richard Hall :
> Thanks for replying, I need all the help I can get. What I'm trying to do is
> the
Thanks for replying, I need all the help I can get. What I'm trying to do
is the opposite of what I seem to be doing. Rather than looking for an
address without a building I am trying to see, from my list of all
buildings, which one has an address (filtered by patientid). I can easily
list all
Thanks for replying to my question.
What I am trying to do is for each building in the list see if there is a
corresponding address record for that building. Thus I'm trying to test the
opposite of what you've pointed out i.e. not that there will be an address
without a building, but if that b
You are assuming you can have address without building.
{% if x.building %}
2017-01-26 0:27 GMT+01:00 Richard Hall :
> Hello, I've only just started with Django and need a bit of help steering
> myself in the right direction.
>
> I want to create a page that has a list of possible forms that could
Hello, I've only just started with Django and need a bit of help steering
myself in the right direction.
I want to create a page that has a list of possible forms that could be
filled in for a patient in a medical study and differentiate between those
forms which have already been completed and
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