Adrian Holovaty wrote:
> On 1/12/06, Jacob Kaplan-Moss <[EMAIL PROTECTED]> wrote:
>
>>On Jan 12, 2006, at 8:09 AM, Simon Willison wrote:
>>
>>>Maybe it would be useful for all Django model objects to gain
>>>themselves a duplicate() method which does exactly this - returns
>>>an identical object
On 1/12/06, Jacob Kaplan-Moss <[EMAIL PROTECTED]> wrote:
> On Jan 12, 2006, at 8:09 AM, Simon Willison wrote:
> > Maybe it would be useful for all Django model objects to gain
> > themselves a duplicate() method which does exactly this - returns
> > an identical object but with id set to None.
>
>
On Jan 12, 2006, at 8:09 AM, Simon Willison wrote:
Maybe it would be useful for all Django model objects to gain
themselves a duplicate() method which does exactly this - returns
an identical object but with id set to None.
+1 -- obj.copy() might be a better syntax to mimic dict.copy().
Ja
Simon Willison wrote:
Maybe it would be useful for all Django model objects to gain
themselves a duplicate() method which does exactly this - returns an
identical object but with id set to None.
There is still complication for non autofield primary key. And it's just
3 lines or under.
--
On 12 Jan 2006, at 05:43, Eric Walstad wrote:
The following approach ('shallow' copy) has worked well for me:
import copy
b = copy.copy(a)
b.id = None
b.save()
Maybe it would be useful for all Django model objects to gain
themselves a duplicate() method which does exactly this - returns an
On Wednesday 11 January 2006 19:00, Mike wrote:
> Hi,
>
> How do I duplicate objects? Save_as style.
>
> Something like...
> a=choices.get_list()[0]
> a.poll_id = 2
> a.save()
>
> Except not to update the previous record
>
> Thanks,
> Mike
The following approach ('shallow' copy) has worked well
On 1/11/06, Dody Suria Wijaya <[EMAIL PROTECTED]> wrote:
> I think you meant __dict__, instead of __dict__(). Secondly, that would
> still copy the primary key, which turns into update query on save.
> An easy way to duplicate in choice case would be to set id as False
> value (0, None, or False),
I think you meant __dict__, instead of __dict__(). Secondly, that would
still copy the primary key, which turns into update query on save.
An easy way to duplicate in choice case would be to set id as False
value (0, None, or False), and thus force the saving routine to generate
a new one and
On 1/11/06, Adrian Holovaty <[EMAIL PROTECTED]> wrote:
> a = choices.get_list()[0]
> a.poll_id = 2
> new_choice = choices.Choice(**a.__dict__())
> new_choice.save()
Oh, uh, wouldn't you not want to assign poll_id at all on the new obj?
Assigning =2 could overlay an existing id r
Thanks Adrian. Very Useful.
Mike
On 1/11/06, Adrian Holovaty <[EMAIL PROTECTED]> wrote:
> For example the following two statements are
> functionally identical:
>
> write_love_letter(to='python', from='adrian')
> write_love_letter(**{'to': 'python', 'from': 'adrian'})
But we'd need unicode to do this:
;-)
write_love_let
On 1/11/06, Mike <[EMAIL PROTECTED]> wrote:
> How do I duplicate objects? Save_as style.
>
> Something like...
> a=choices.get_list()[0]
> a.poll_id = 2
> a.save()
>
> Except not to update the previous record
You could do this:
a = choices.get_list()[0]
a.poll_id = 2
new_choice = cho
Hi,
How do I duplicate objects? Save_as style.
Something like...
a=choices.get_list()[0]
a.poll_id = 2
a.save()
Except not to update the previous record
Thanks,
Mike
13 matches
Mail list logo
