Re: Get url parameters

Hi I need to get a parameter from the url which is the id and do not know how. When my url is like this: * http://localhost:8080/test/view/20519364e38774a71190edb28c* I do: *url(r'^view/(?P\w+)', 'rest.views.view'),* And everything ok. Now I have a url like this: *

Re: Get url parameters

gfsp = GridFSProxy() gfsp.variable Where variable is the variable name that contains the data storing the number you want yo retrieve. I think it can solve your problem. 2013/5/15 Hélio Miranda : > So I mean the client side in my application I have to be able to access only >

Re: Get url parameters

So I mean the client side in my application I have to be able to access only the id, then just send the id and not ? Could not sending as it is in django to extract just the number of the url? -- You received this message because you are subscribed to the Google Groups "Django users" group.

Re: Get url parameters

Your view is returning a GridFSProxy object, not a class/method variable. You've to call a instance of your GridFSProxy, so you'll can access the relative data. 2013/5/15 Hélio Miranda : > Hi > > I need to get a parameter from the url and do not know how. > If my url looks

Get url parameters

Hi I need to get a parameter from the url and do not know how. If my url looks like this: * http://localhost:8080/test/view/20519364e38774a71190edb28c* I did like this: *url(r'^view/(?P\w+)', 'rest.views.view'),* And everything ok. Now I have a url like this: *http://localhost:8080/test/view/*