Re: Getting the first item in a dict

I ended up using `dict[next(iter(dict))]` I am getting the dict as one of two dicts nested in a list from a weather service API. I do this using a list comprehension to call the API with coordinates for each location in another list. A mouthful. `resp = [fetch_api_data(location, request_id) for

Re: Getting the first item in a dict

Note that these give the only value. This won't work if you have more than one value in the dict, since you won't know which you will get. Where d is the dict: list(d.values())[0] or for i in d.values(): # use i here print(i) or d[list(d)[0]] I'm sure that there

Re: Getting the first item in a dict

show you the first item unless it was an > ordered dict. > > Mike > > > > > > Original message > From: S D > Date: 27/1/20 22:56 (GMT+10:00) > To: django-users@googlegroups.com > Subject: Getting the first item in a dict > > I have a diction

RE: Getting the first item in a dict

Can you use ddict[ddict.keys()[0]] ???I don't know if that would show you the first item unless it was an ordered dict. Mike Original message From: S D Date: 27/1/20 22:56 (GMT+10:00) To: django-users@googlegroups.com Subject: Getting the first item in a dict I have

Getting the first item in a dict

I have a dictionary which contains one item (“current_location”, which is a nested dict) and I would like to access that nested dict. However, I cannot use the key as the code will break if a different key is passed, e.g. “different_location”. How can I access the first item in a dictionary