Re: How to pass a string as url's parameter

Thanks you all Snejy and James. Regards > -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group,

Re: How to pass a string as url's parameter

You can do fruit = get_object_or_404(Fruit, name=fruit_name) but i wont recommend doing this with field that is not unique because it basically resolves to Fruit.objects.get(name=fruit_name) which will raise error if there are two objects with the same name... Furthermore you have choices..

Re: How to pass a string as url's parameter

If I understand the question correct.. you can do fruit = get_object_or_404(Fruit, name=fruit_name) even if its not SlugField. I dont recommend doing that with field that doesn't have unique=True because error will be raised if there are more than one objects with this name. (This equals

Re: How to pass a string as url's parameter

You probably don't want to use the name directly, you should probably look at creating a slug from the name and store it in a SlugField on your model. https://docs.djangoproject.com/en/1.8/ref/models/fields/#slugfield https://docs.djangoproject.com/en/1.8/ref/utils/#module-django.utils.text Your

How to pass a string as url's parameter

Hi evrybody, Here is my model: # fruits/models Class Fruit (models.Model): name = models.CharField(max_length = 33, choices = NAME_CHOICES, default = MANGO) # and so on... # fruits/views def fruit(request, fruit_name): fruit =