On Tue, Nov 17, 2009 at 9:03 AM, Ilya Polosuhin wrote:
> I don't fully understood your question. Of course I have more than one row
> at test_mymodel2
> SQL query was formed by django-ORM. I just call
> print (MyModel.objects.filter(key_to_mymodel2 =
>
I don't fully understood your question. Of course I have more than one row
at test_mymodel2
SQL query was formed by django-ORM. I just call
print (MyModel.objects.filter(key_to_mymodel2 =
MyModel2.objects.all()))._as_sql())
and write here output.
And I also googled for this MySQL error and found
On Tue, Nov 17, 2009 at 7:17 AM, Ilya wrote:
> I just developed some code like:
> MyModel.objects.filter(key_to_mymodel2 = MyModel2.objects.all()))
> This query produce SQL:
> SELECT * FROM `test_mymodel` WHERE key_to_mymodel2_id =(select `id`
> from `test_mymodel2`)
>
M, thanks.
But should I create ticket on django trac about this issue?
On 17 ноя, 17:29, Tom Evans wrote:
> On Tue, Nov 17, 2009 at 3:17 PM, Ilya wrote:
> > I just developed some code like:
> > MyModel.objects.filter(key_to_mymodel2 =
On Tue, Nov 17, 2009 at 3:17 PM, Ilya wrote:
> I just developed some code like:
> MyModel.objects.filter(key_to_mymodel2 = MyModel2.objects.all()))
> This query produce SQL:
> SELECT * FROM `test_mymodel` WHERE key_to_mymodel2_id =(select `id`
> from `test_mymodel2`)
>
I just developed some code like:
MyModel.objects.filter(key_to_mymodel2 = MyModel2.objects.all()))
This query produce SQL:
SELECT * FROM `test_mymodel` WHERE key_to_mymodel2_id =(select `id`
from `test_mymodel2`)
It works fine on SQLLite, but in MySQL it produce error:
OperationalError: (1242,
6 matches
Mail list logo