>
>
>>
>>
>>
>> {% if object_list.has_previous %}
>>
>> first
>>
>> previous
>>
>> {% endif %}
>>
>>
>>>
>>
>> Page {{ object_list.number }} of {{
>>> object_list.paginator.num_pages }}.
>>
>>
>>
>>
>>> {% if
Would you send your html codes relating to pagination
در تاریخ چهارشنبه ۲۵ سپتامبر ۲۰۱۹، ۱۵:۰۳ leb dev
نوشت:
> i tried your answer and display an error :
>
> That page number is not an integer
>
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> "Django users"
i tried your answer and display an error :
That page number is not an integer
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Try this one :
paginator = Paginator(queryset_list,8) # Show 25 contacts per page
page_request_var = "page"
page = request.GET.get(page_request_var)
try:
queryset = paginator.page(page)
except PageNotAnInteger:
# If page is not an integer, deliver first page.
queryset =
no i am using function based views
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Hi,
Do you use Class Based View ?
Sent from Mail for Windows 10
From: leb dev
Sent: Wednesday, September 25, 2019 2:32 PM
To: Django users
Subject: where is the error in pagination?
i have a django project and it includes pagination i do not know where is the
error in my code but once i
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