Re: Unexpected keyword argument when calling a function

2007-07-07 Thread Greg
Karen, Thanks...that is exactly what happened. I copied the old function but forgot to delete it Thanks On Jul 7, 7:05 pm, "Karen Tracey" <[EMAIL PROTECTED]> wrote: > On 7/7/07, Greg <[EMAIL PROTECTED]> wrote: > > > > > I done this before with just one variable and it's always been (? > > P\d+

Re: Unexpected keyword argument when calling a function

2007-07-07 Thread Karen Tracey
On 7/7/07, Greg <[EMAIL PROTECTED]> wrote: > > I done this before with just one variable and it's always been (? > P\d+). Can I change the name from object_id to > manufacturer_id and collection_id? And can I send two variables > (three including request)? Yes, you can change the names and you

Re: Unexpected keyword argument when calling a function

2007-07-07 Thread Todd O'Bryan
According to the code I have, this should be working. Try changing it to def showcollection(request, manufacturer_id=None, collection_id=None): and see if that makes any difference. On Sat, 2007-07-07 at 16:07 -0700, Greg wrote: > Hello, > I have the following line in my urls.py file > > r'^(

Unexpected keyword argument when calling a function

2007-07-07 Thread Greg
Hello, I have the following line in my urls.py file r'^(?P\d+)/(?P\d+)/styles/$', 'mysite.rugs.views.showcollection'), // I have the following function defined in my views.py file def showcollection(request, manufacturer_id, collection_id): s = Style.objects.filter(