My models are defined like this:
class Problem(models.Model):
title = models.CharField('Title', max_length = 100)
question = models.TextField('Question')
class Submission(models.Model):
user = models.ForeignKey(User)
problem = models.ForeignKey(Problem)
solution =
http://docs.djangoproject.com/en/dev/ref/models/querysets/#distinct
Distinct() may be what you're looking for to returns distinct values
for each problem.
Or, petter yet, you could use .latest()
So Submission.objects.all().latest('problem').distinct()
On Aug 14, 5:57 pm, Kenneth Gonsalves wrote:
> On Sat, 2010-08-14 at 05:45 -0700, Rohan Jain wrote:
> > I have a field 'submission' which has a 'user' and a 'problem'.
> > How can i get a django queryset search result which will give a list
> > of only one result per
Actually there may be many submissions with a user-problem pair but i
want to list only the last one per user - problem pair.
Like:
let p1 be two problems , u1, u2 be two users and s1,s2 two submissions
by user u1 on problem and s3,s4 by u2.
so i want to get a queryset with only the last
On Sat, 2010-08-14 at 05:45 -0700, Rohan Jain wrote:
> I have a field 'submission' which has a 'user' and a 'problem'.
> How can i get a django queryset search result which will give a list
> of only one result per user-problem pair.
does your model not have a unique_together for user and
I have a field 'submission' which has a 'user' and a 'problem'.
How can i get a django queryset search result which will give a list
of only one result per user-problem pair.
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