I fixed it with the not recommended method, but/so any help fixing it
the other way would be appreciated
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Ok I did as much of that as I could. I could not return
render_to_response('template.html', c) because I have a dict of other
values I must send, such as the form and the results.
Now I get:
"Reason given for failure:
No CSRF or session cookie.
"
probably because of that one thing
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I'll look at that article, thanks!
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Hmm,
have you checked documentation [1] at all? The token is not the only
thing, you need to enable a middleware too (a few things are needed
basically).
Cheers
Jirka
[1] http://docs.djangoproject.com/en/dev/ref/contrib/csrf/
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I tried to make a quick search box for my site-in-progress and
expected it to be as simple as keeping the database updated.
Unfortunately I ran into the following error as soon as I POSTed a
query:
[QUOTE]
Forbidden (403)
CSRF verification failed. Request aborted.
Help
Reason given for failure:
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